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Mathematics 39 Online
OpenStudy (anonymous):

if angle 1 = 50 degrees and angle DAB = 35 degrees, find arc AC and m of angle ABC

OpenStudy (anonymous):

OpenStudy (anonymous):

I do know whatever arc AC is will be the same for angle ABC

OpenStudy (anonymous):

If I add 35 + 50 = 85/2 = 42.5???

OpenStudy (anonymous):

Yes this one.

OpenStudy (watchmath):

Do we know if BC passes through the origin?

OpenStudy (watchmath):

I mean the center

OpenStudy (anonymous):

it doesnt show a center. because E is definitely not in the center

OpenStudy (anonymous):

But yes BC passes through E and so does AD

OpenStudy (watchmath):

Ok first let's find \(\angle ABC\)

OpenStudy (anonymous):

when I use the formula when two cords of a circle intersect, the measure of each angle formed is one-half the sum of the measures of its intercepted arc and the arc intercepted by its vertical angle.

OpenStudy (anonymous):

I get that 42.4 number a degree can not be that

OpenStudy (watchmath):

Note that we can find angle AEB. Then you can find angle ABC.

OpenStudy (anonymous):

180-50 = 130

OpenStudy (watchmath):

Good! so now what is the angle of ABC?

OpenStudy (anonymous):

180- 130 = 50 no?

OpenStudy (anonymous):

its too small to be 50

OpenStudy (watchmath):

Sorry... AEB = 180 - angle 1 = 180 -50 = 130.

OpenStudy (anonymous):

ok so Angle AEB is 130 and we know angle A is 35 add those and subtract 180 gets me 15 degrees?

OpenStudy (watchmath):

Great! :)

OpenStudy (anonymous):

So if angle ABC is 15 degrees then the arc AC is 15

OpenStudy (watchmath):

Are we looking for the length of the arc AC or the angle measure of the arc AC ?

OpenStudy (anonymous):

the measure of arc AC and the measure of angle ABC

OpenStudy (watchmath):

Ok, the 15 is the inscribed angle of AC, so the central angle is twice of that, which is 30.

OpenStudy (anonymous):

ok... this is because the angle of ABC is inside a triangle right...

OpenStudy (watchmath):

yes

OpenStudy (anonymous):

thank you

OpenStudy (watchmath):

If I am not around and you have a question you can ask me here: http://www.ask.watchmath.com :D

OpenStudy (anonymous):

oh thank you!

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