Question

The perimeter of a rectangle is 158 inches. The length exceeds the width by 57 inches. Find the length and the width.

Answer 1

2l+2w=158 is given in the first sentence

Answer 2

l=w+57 is given by second sentence

Answer 3

L=length, W=width
Then 2L+2W=158.
Also L=W+57
Plug in that to the first equation we have
2W+114+2W=158
4W=44
W=11
Hence L=68

Answer 4

so 2(w+57)+2w=158
2w+2(57)+2w=158
4w+2(57)=158
4w=158-2(57)=158-114
4w=44
w=44/4=11
so
l=11+57=68

Answer 5

Thank you :)