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OpenStudy (anonymous):
The perimeter of a rectangle is 158 inches. The length exceeds the width by 57 inches. Find the length and the width.
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myininaya (myininaya):
2l+2w=158 is given in the first sentence
myininaya (myininaya):
l=w+57 is given by second sentence
OpenStudy (watchmath):
L=length, W=width Then 2L+2W=158. Also L=W+57 Plug in that to the first equation we have 2W+114+2W=158 4W=44 W=11 Hence L=68
myininaya (myininaya):
so 2(w+57)+2w=158 2w+2(57)+2w=158 4w+2(57)=158 4w=158-2(57)=158-114 4w=44 w=44/4=11 so l=11+57=68
OpenStudy (anonymous):
Thank you :)
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