Question

Amistre64, still there in the sky?

Answer 1

whattup??

Answer 2

Need to combine piecewise functions. Here they are. Give me a sec.

Answer 3

with no money and no gas and no food; playing in here takes my mind off of the rest of that stuff :/

Answer 4

-(x-2), x<2
x-2, x>or=to 2 This is one piecewise.

-(x+6), x<6
x+6 x>or=to -6. This is the second part. Need to combine and simplify. How to do?

Answer 5

I know what you mean about no money, or gas and everything else! I am in the same boat in Illinois, but with nowhere near your brains! You one-upped me!

Answer 6

I'd rather be poor and starving and smart than poor starving and dumb!

Answer 7

:)

Answer 8

the 'or' means that the domain is a part of both sets

Answer 9

read it wrong :)

-(x-2) ; (-inf,1)

x-2; [2,inf) .......This is one piecewise.
...........................................
-(x+6) ; (-inf,6) <- is this a typo? maybe meant -6?

x+6 ; [-6,inf)

Answer 10

these are piecewise functions that define absolute value functions...

Answer 11

You know I forgot to type in the interval. Let me try to use the equation thing and type the whole thing, ok?

Answer 12

ok :)

Answer 13

Ok, I can'g even figure out the equation thing so here goes in long-hand style. : (

Answer 14

Apparetnly, I can't ype either. oops, I mean I can't type, either! Or spell!

Answer 15

the first piecewise combines and simplifies to:

f(x) = |x-2|

teh second one combines and simplifies to:

g(x) = |x+6|

Answer 16

does that help?

Answer 17

-(x-2), x<2
x-2, x>2

-(x+6), x<6
X+6, x>-6 Combine and simplify. The interval is -8<x<8

Answer 18

Ugh! Those are not right either!

Answer 19

Let me tell you that in both of those piecewise functions, the second "x is greater than" is supposed to be "greater than or equal to".

Answer 20

Did you hang up on me?

Answer 21

im here

Answer 22

do we have any options to determine if we are in the right ball park?

Answer 23

Do you want me to go back to MathXL and get the answer and give it to you so you know?

Answer 24

itd be helpful; because I got a notion that its gonna look like this:

f(x) =:

|x+6| ; [-8, y]

|x-3| ; [x,8]

Answer 25

well, the x, y stuff is from something else in me head lol

Answer 26

This is it, combined and simplified. BTW, I thought simplified was the shorter, easier version?!
-2x-4, -8<x<-6
8 -6<x<2
2x+4, 2<x<8

Answer 27

|x+6| ; [-8, n]

|x-3| ; [n,8]

n = where the graphs meet

Answer 28

Again, in the first inequality, it is supposed to be -8 is less than or equal to x is less than -6

Answer 29

The second line is supposed to be -6 is less than or equal to x is less than or equal to 2

Answer 30

The third line is supposed to be 2 is less than x is less than or equal to 8

Answer 31

Did you get all that or are you so sick of me you could scream?

Answer 32

right.... i got no idea how they did that tho :/

Answer 33

do you have a link to the material you are studying>?

Answer 34

I'm taking calc online with GCU and it's through MathXL, their math program. I don't know if I can send you a link. Let me check.

Answer 35

I cannot get a link and the problem shows that it takes 22 steps to figure it out! We are working with extrema with regards to where functions are undefined, where they equal zero, and then find the local min and max values.

Answer 36

i havent worked with piecewise functions in calculs yet; i heard they were out there, bit just havent seen that bear yet lol

Answer 37

I will try to get something online and send it. TTYSoon, Rachel. ps. you're awesome! Thanks for the time again. I'll be back!

Answer 38

youre welcome :)