Question

How do you simplify (secx-1)/tanx to tan(x/2) ??

Answer 1

secx=1/cosx, tanx=sinx/cosx

so we have ((1/cosx)-1)/(sinx/cosx)=(1-cosx)/(sinx)

Now, 1-cosx=2sin^2(x/2) and sinx=2sin(x/2)cos(x/2)

So, 2sin^2(x/2)/(2sin(x/2)cos(x/2))=sin(x/2)/cos(x/2)=tan(x/2)

Answer 2

Thanks alot !

Answer 3

your welome :)

Answer 4

you're *

Answer 5

welcome*