Question

write the standard form of the equation of the circle:
x^2+y^2-2x+6y+6=0

Answer 1

the form u wrote is the standard form:)

Answer 2

no. standard form is: (x-h)^2+(y-k)^2=r^2

Answer 3

Yeah you have to complete the square, you got your notes on that nomss?

Answer 4

might have to complete the square

Answer 5

there is an example in the book

Answer 6

(x-1)^2+(y+3)^2=2^2

Answer 7

(x^2-2x+1) +(y^2+6y+9)=-6+9+1

Answer 8

I have this: (x^2-2x+1) +(y^2+6y+9)=-6+9+1, what now? I don't think I can do (x+1)^2 + (y+3)2 = 4?

Answer 9

right
(x-1)^2+(y+3)^2=2^2

Answer 10

cool, i see, thanks.