Question

The circle intersects the line with he equation x+y=3 at 2 points, A and B.
Find algebraically the coordinates A and B

show the distance AB= sqrt 162

thanks :)

Answer 1

what line?

Answer 2

a circle equation has an equation of x6@+y^2=45
is that what you mean?

Answer 3

MissMys, you just wrote something in the comments? is that more info about this problem?

Answer 4

yes :)

Answer 5

Well you have to write the whole question word for word as i was given to you, in order for us to be of any help.

Answer 6

a circle equation has an equation of x^2+y^2=45

The circle intersects the line with he equation x+y=3 at 2 points, A and B.
Find algebraically the coordinates A and B

show that the distance AB is sqrt 162

and the previous qs asks about radius and centre of the circle

Answer 7

Put the two equations together, you would find to values for y=3, y=34. You can use these values to obtain related values for x. The two x,y values should be point A and B. You can double check it with distance formula.

Answer 8

sorry but i dont understand? :S
so do i put those two values into the equation??

Answer 9

You have your equation for the line, you can solve for x, or y. From your line equation, x=3-y. Put this in the circle equation. (3-y)^2+y^2=45. I have already done this much for you, the result is y=3, y=34

Answer 10

urm, i havent got a clue what you did and 34 is wrong :S
i am so dead tomorrow :(

Answer 11

i understand the first bit then confused of how you got 3 and 34 :S

Answer 12

Well forget about 3 and 34. Solve for y from the new equation created.

Answer 13

thanks for helping but i cant do it :(
ill still give u the medal :)

Answer 14

What can't you do? You have an equation (3-y)^2+y^2=45, solve for y.

Answer 15

yea i dunno what or how you do the squared bit :(

Answer 16

\[(3-y)^{2}=(3-y)(3-y)\]

Answer 17

thanks :)