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write an equvilant logarithmic equation from each exponential equation 3 exponent 3 = 27.................5 negative exponent 2 = 1/25
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\[3^3 = 27\]\[\log_{3}27 = 3 \]\[5^{-2} = 1/25\]\[\log_{5}(1/25) = -2 \]
ok sooo thanks but can you explain please
so i do it in exponential its going in reverse
?
Here's the rule (you need to memorize this: if: \[ a^b = c\] then:\[\log_{a}c = b \]
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ok thaks and if i do it exponential its puting back to were the equation is to be solved as in logarithmic
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