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Mathematics 13 Online
OpenStudy (anonymous):

SOLVE FOR X

OpenStudy (nowhereman):

what?

OpenStudy (anonymous):

mmm?

OpenStudy (anonymous):

\[(1 \ 3)^{4x-1}=3^{x-1}\]

OpenStudy (anonymous):

(1/3)*****

OpenStudy (nowhereman):

well, you know exponentiation rules, don't you?

OpenStudy (anonymous):

not really.. :x

OpenStudy (anonymous):

x≈0.4

OpenStudy (anonymous):

I dont understand what that means can you show me how you got that answer norbeybarajas

OpenStudy (anonymous):

-________- I dont understand what im looking at when i look at that..

OpenStudy (nowhereman):

you have to multiply the equation by \(3^{4x-1}\) to get all the x on one side and then you just simplify, until you can take the logarithm.

OpenStudy (anonymous):

i still dont understand but thanks

OpenStudy (nowhereman):

Then show your calculations and where you don't know what to do.

OpenStudy (anonymous):

i dont even know how to start the problem..

OpenStudy (nowhereman):

I just told you.

OpenStudy (anonymous):

where are you getting that though you combined both sidfes of the equal sign..

OpenStudy (nowhereman):

If you multiply both sides by that term you will get just "1" on one side and the terms with x on the other.

OpenStudy (anonymous):

I really dont understand what your saying where did you get 3^4x-1 its either 3^x-1 or 1/3^4x-1

OpenStudy (nowhereman):

\(3^{4x-1} \cdot (\frac{1}{3})^{4x-1} = 1\) that is why you should really look at those rules!

OpenStudy (anonymous):

I did/ i am i dont know what im even looking at !!!!! :[ i just need someone to explain it from the first to last step or before i can solve it..

OpenStudy (nowhereman):

Maybe you should start with some easier exponential calculations then.

OpenStudy (anonymous):

This is on a passed regents exam..... i dont even remeber doing this

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