Question

Solve using the quadratic forumula.

3x^2 + x - 4 = 0

Answer 1

Do you know the quadratic formula?
\[-b \pm \sqrt{b ^{2}-4ac}/2a\]

Answer 2

Then it's just a matter of plugging in the values and simplifying.

Answer 3

3x^2+4x-3x-4=0
(x-1)(3x+4)=0

Answer 4

x=1,-4/3

Answer 5

I understand how to substitute everything in, but from there I am unsure how to simplify -1 ± 12−4*3*4−−−−−−−√

Answer 6

-1 +/- sqrt -48

Answer 7

a=3,b=1, c=-4

Answer 8

Work on the square root part first. \[\sqrt{1^{2}-4*3*-4}\]

Answer 9

You missed a couple things in the sqrt. \[1^{2}=1\]

4*3*-4=-48

1-(-48)

Answer 10

Get that? So it's \[\sqrt{1+48}=\sqrt{49}=7\]

So, \[(1 \pm 7)/6\]

Answer 11

Thank you very much! That makes much more sense now. Once again, thanks!

Answer 12

np.