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Mathematics
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√9 over √75
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\[\sqrt{3}/5\]
\[\sqrt{9} = 3\] \[\sqrt{75} = \sqrt{25\times 3} = 5\sqrt{3}\] therefore \[3/5\sqrt{3}\] multiply top and bottom by \[\sqrt{3}\] so we have \[3\sqrt{3}/5\sqrt{3}\sqrt{3}\] \[= 3\sqrt{3}/5 \times 3\] \[= \sqrt{3}/5\]
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