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Mathematics 7 Online
OpenStudy (anonymous):

simplify √54x^7y^10

OpenStudy (owlfred):

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OpenStudy (shadowfiend):

Remember that square root is the same as dividing powers by 2. Also, 54 = 7 x 8 = 7 x 4 x 2 = 4 x 28 So, we have: \[\sqrt{4 \cdot 28 x^7 y^{10}}\] We can take the square root of 4 and pull it out: \[2\sqrt{28x^7y^{10}}\] And we can divide 10 by 2, since the square root is the same as dividing the power by 2: \[2y^5\sqrt{28x^7}\]

OpenStudy (anonymous):

you can do more i think. \[x^7=x^6\times x\] and \[\sqrt{x^6}=x^3\] also \[2\times 7=14\] so answer should be \[2x^3y^5\sqrt{14x}\]

OpenStudy (roadjester):

i have one problem with that answer. 8*7=56, 6*9=54 so that coefficient is wrong

OpenStudy (anonymous):

\[\sqrt{54x^3 y^2}\]

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