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Mathematics 11 Online
OpenStudy (anonymous):

lim x -> 0 (x-1)/(3sin(x) - cos(x))

OpenStudy (anonymous):

evaluate the limit of the trigonomoteric limit

myininaya (myininaya):

(0-1)/(3sin(0)-cos(0)) =-1/(3*0-1) =-1/(0-1) =-1/(-1) =1

OpenStudy (anonymous):

we cant substitute first

myininaya (myininaya):

the function is continuous at x=0 so yes we can

OpenStudy (anonymous):

:s ok i guess

OpenStudy (anonymous):

so thats not the same as lim x-> 0 2sin (3x)/ 5x which would be equal to 6/5?

myininaya (myininaya):

this function is discontinuous at x=0 we can manipulate this function though to see what happens as x->0 remember sinx/x->1 as x->0 so 3/3*2sin(3x)/5x=6/5*sin(3x)/3x=6/5*(1) since sin(3x)/3x->1 as x->0

OpenStudy (anonymous):

ok thank you i get it

OpenStudy (anonymous):

i forgot about continuity

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