Question

graph the system of inequalities
y>-3
y<- abs(x+2)
which two quadrants does the solution lie in?
possible answers
2 and 3
1 and 2
1 and 4
3 and 4

Answer 1

what is the second inequality?

Answer 2

y<- abs(x+2)

Answer 3

abs?absolute?

Answer 4

absolute
so its 1 and 2

Answer 5

amistre she has to answer 'AND'

Answer 6

0 < -|2| ; i shaded a wrong area lol

Answer 7

y < -3 means in quadrants III or IV since below the x axis.

Answer 8

thats what i was confused

Answer 9

but the absolute is where i am stuck

Answer 10

then the second inequality says -x-2<y<x+2

Answer 11

so has be in quad III

Answer 12

oh damn

Answer 13

my mistake. first one says y > -3 sorry

Answer 14

(0,0) is a false solution to the abs...

Answer 15

sorry sorry i messed up

Answer 16

your sleepy aren't you satellite lol

Answer 17

and I lifted instad of sepereted my graph...

Answer 18

lol back at square one

Answer 19

yeah i missed the inequality, my fault. i had it backwards

Answer 20

this is it lol

Answer 21

3 and 4

Answer 22

3 and 4

Answer 23

amistre...is it a final attachment :p

Answer 24

lol..... maybe ;)

Answer 25

..ammendment D lol

Answer 26

no moving towards the final solutions;)

Answer 27

yes it is 3 and 4. y =- |x+2| upside down v at (-2,0) so y<-|x+2| everything below that. must be in 3 or 4. there is just a tiny piece in 4