Question

When dividing rational expressions (P(x)/Q(x) divided by R(x)/S(x)), is this expression undefined when any of Q(x), R(x), or S(x) undefined?

Answer 1

my guess is yes; when a peice is undefined that usually puts a damper on things

Answer 2

Sorry, I meant when any of those 3 are 0.

Answer 3

Q(x) cant be zero; and R(x) cant be zerp

Answer 4

zerp is like a zero but only got its GED

Answer 5

S(x) can't be zero either though, because if it were, S(x)/R(x) would be 0 and that would be dividing the first part by 0, right?

Answer 6

You are correct

Answer 7

Sorry, I got screwed up, I meant it would make S(x)/R(x) undefined and thus the whole thing. Okay, I just wanted to make sure it was any of the 3.

Answer 8

P(x)
----
Q(x) <- cant be zero
-------
R(x) <- cant be zero
---
S(x) <- cant be zero

Answer 9

Perfect.