When dividing rational expressions (P(x)/Q(x) divided by R(x)/S(x)), is this expression undefined when any of Q(x), R(x), or S(x) undefined?

Question

amistre64 · Answer

my guess is yes; when a peice is undefined that usually puts a damper on things

anonymous · Answer

Sorry, I meant when any of those 3 are 0.

amistre64 · Answer

Q(x) cant be zero; and R(x) cant be zerp

amistre64 · Answer

zerp is like a zero but only got its GED

anonymous · Answer

S(x) can't be zero either though, because if it were, S(x)/R(x) would be 0 and that would be dividing the first part by 0, right?

amistre64 · Answer

You are correct

anonymous · Answer

Sorry, I got screwed up, I meant it would make S(x)/R(x) undefined and thus the whole thing.  Okay, I just wanted to make sure it was any of the 3.

amistre64 · Answer

P(x)
  ----
   Q(x)   <-  cant be zero
-------
   R(x)   <-  cant be zero
   ---
   S(x)   <-  cant be zero

anonymous · Answer

Perfect.