Question

can anyone solve for v?
-3v/v+3=-9/v^2+v-6

Answer 1

-3v^3 -3v^2 + 6v = -9v - 27

Answer 2

is right hand side = -9 / (v^2+v-6) ?

Answer 3

what i mean is are all three terms in the bottom of fraction?

Answer 4

are u there nest?

Answer 5

\[\frac{-3v}{v+3}=\frac{-9}{v ^{2}+v-6}\]\[\frac{-3v}{v+3}=\frac{-9}{(v+3)(v-2)}\]\[-3v(v-2)=-3v ^{2}+6v\]\[-3v ^{2}+6v=-9\]\[-3v^2+6v+9=0\]\[-3(v ^{2}-2v-3)=0\]\[(v+1)(v-3)=0\]\[v=3 \]\[ v =-1\]