Question

In each part, rewrite the expression as a ratio of polynomials:
a) cosh(In x)
b) sinh (In x)
c) tanh (2 In x)
d) cosh (-In x)

Answer 1

\[\cosh(lnx) = [e^lnx + e^-lnx]/2 from definition of \cosh\]

Now \[e^lnx =x\]

So cosh(lnx) = \[[x +1/x]/2 = [x^2 + 1]/2xThe others are done the same way\]