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Mathematics 51 Online
OpenStudy (anonymous):

In each part, rewrite the expression as a ratio of polynomials: a) cosh(In x) b) sinh (In x) c) tanh (2 In x) d) cosh (-In x)

OpenStudy (anonymous):

\[\cosh(lnx) = [e^lnx + e^-lnx]/2 from definition of \cosh\] Now \[e^lnx =x\] So cosh(lnx) = \[[x +1/x]/2 = [x^2 + 1]/2xThe others are done the same way\]

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