Question

im trying to do my math hw but i dont get it we are studying Quadratic functions abd the function is y=x^2-10x+2 help please :((

Answer 1

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

Answer 2

First of all: Don't call yourself a math retard

Answer 3

lol

Answer 4

haha (:

Answer 5

the first step is do not be negative lol

Answer 6

haha

Answer 7

what would you like to do with the "quady"

Answer 8

lol ok ok but can i get some gelp :/

Answer 9

*help

Answer 10

Second of all: Its just like solving an algebraic equation

Answer 11

i like gelp better

Answer 12

same lol

Answer 13

lol i know its the same but i juss dnt get it

Answer 14

so do you want to graph the "quady"?

Answer 15

silence satellite!

Answer 16

i dnt think im supposed to graph i think i juss needa find the vertex and coordinates :/ or maybe i am idk >.<

Answer 17

myininaya izzat you?

Answer 18

omg 465 so lame you are leaving me in the dust
the more we find the better are graph will look
lets start out with x-intercepts

Answer 19

to find x-intercepts, set y=0 and solve for x

Answer 20

x^2-10x+2=0

Answer 21

okk then what :o

Answer 22

now this is totally not factorble so you have to use the quady formula!

Answer 23

\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

Answer 24

satellite i was kidding you can talk lol

Answer 25

\[x=\frac{10 \pm \sqrt{10^2-4(1)(2)}}{2(1)}\]

Answer 26

sooo after tht wat next o.o

Answer 27

\[x=\frac{10 \pm \sqrt{100-8}}{2}=\frac{10 \pm \sqrt{92}}{2}=\frac{10 \pm \sqrt{4*23}}{2}\]

Answer 28

\[x=\frac{10 \pm 2\sqrt{23}}{2}=5 \pm \sqrt{23}\]

Answer 29

lordamercy
\[x^2-10x+2=0\]
\[x^2-20x=2\]
\[(x-5)^2=-2+25=23\]
\[x-5=\pm\sqrt{23}\]
\[x=5\pm\sqrt{23}\]

Answer 30

so these two are where your graph is going to the intercept the x axis

Answer 31

satellite used completeing the square (which is used to proved the quady formula is the solution of the quady equation)

Answer 32

oops typo. second line should have been
\[x^2-10x=-2\]

Answer 33

also it is nice to use when the middle coefficient is even so you do not have to simplify the radical, factor and cancel

Answer 34

yes that too

Answer 35

the quadratic formula forces a denominator on you but you see that there isn't one!

Answer 36

i will be quiet now

Answer 37

now lets take a break now from the hard stuff and see if we can find a y-intercept

Answer 38

to find the y-intercept, set x=0 and solve for y

Answer 39

y=0^2-10(0)+2=0-0+2=2

Answer 40

smhh i know you guys are gonna get mad but...i still dnt get it :[

Answer 41

i'm furious lol

Answer 42

i'll just take my frends answers in school tommorow lol

Answer 43

i was kidding

Answer 44

what part is getting you down?

Answer 45

i know lols

Answer 46

the whooooole thing D:

Answer 47

do you know the quadratic formula?

Answer 48

ax^2=bx+c?

Answer 49

*ax^2+bx+c

Answer 50

\[ax^2+bx+c=0\] -> quad equation
\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\] -> quad formula (solution to the quad equation)

Answer 51

mhmm :x

Answer 52

i thought it was just -b/2a

Answer 53

no

Answer 54

wow ok :/

Answer 55

bt anyway i go sleep now lols so ttyl

Answer 56

ok gn

Answer 57

gn ^_^