Question

Find the center of the circle defined by the equation
x^2+y^2-4x-4y+4=0

Answer 1

You want to complete the square for x and y.
\[x^2-4x+(4-4)+y^2-4y+(4-4)+4=(x-2)^2+(y-2)^2=4\]

Answer 2

So your center is (2,2)

Answer 3

^ was going to write the exact thing lol

Answer 4

:P

Answer 5

Thanks love!

Answer 6

No problem :P