g=[(-7,-5) , (-4,-7) , (5,0) , (9,6)]
h(x)=2x-3

find g^-1(-7)=?
h^-1(x)=?
(h times h^-1)(3)=?

Question

g=[(-7,-5) , (-4,-7) , (5,0) , (9,6)]
h(x)=2x-3

find g^-1(-7)=?
       h^-1(x)=?
       (h times h^-1)(3)=?

anonymous · Answer

$$g(-4)=-7$$ so $$g^{-1}(-7)=-4$$

anonymous · Answer

h says mulitiply by 2, subtract 3 so 
$$h^{-1}$$ will say add 3 divide by 2
$$h^{-1}(x)=\frac{x+3}{2}$$

anonymous · Answer

if that is too annoying think about solving this
2x+3=11 steps are subtract 3 divide by 2 to get x = 4
now if we have y = 2x +3 and we want to solve for x we write
 y - 3 = 2x or x = (y-3)/2 and that is your inverse

anonymous · Answer

and finally it is not times, it is "of" 
not 
$$h\times h^{-1}(x)$$ but rather 
$$h(h^{-1}(x))$$
and 
$$h(h^{-1}(x))=x$$ because when you compose a function with its inverse you get what you started with