Question

H(t)=-16t2+96t
Find the vertex. (show steps please, I'm so confused!)

Answer 1

vertex use
\[-\frac{b}{2a}\]

Answer 2

in this case a = -16, b = 96 to
\[-\frac{b}{2a}=-\frac{96}{2\times -16}=3\]

Answer 3

3 is the first coordinate and \[H(3)=-16\times 3^2+96\times t =144\]

Answer 4

so vertex is (3,144)

Answer 5

if the question is "how high does the ball go?" the answer is the max is 144 ft after 3 seconds

Answer 6

steps clear?