is this right?
12x^2+5x=3
-3
12x^2+5x-3=0
(3x+1)(4x-3)
3x+1=0 4x-3=0
-1 +3
3x=-1 4x=3
x=-1/3 x=3/4 if not tell me were i went wrong

Question

is this right?
12x^2+5x=3
                 -3
12x^2+5x-3=0
(3x+1)(4x-3)
3x+1=0 4x-3=0
      -1          +3
3x=-1 4x=3
x=-1/3 x=3/4 if not tell me were i went wrong

anonymous · Answer

should be (3x-1)(4x+3)

anonymous · Answer

okay bc its a positive 5 right?

anonymous · Answer

You're right except your signs are backward.

anonymous · Answer

okay, i have a problem with my signs, i really get confused on were to place them

anonymous · Answer

$$(3x-1) = 0 \iff x = 1/3$$
$$(4x + 3) = 0 \iff x = -3/4$$
$$(3x-1)(4x+3) = 0 \iff x = 1/3\ \text{ or }\ x = -3/4$$
And yeah, if you foil it out you'll see that you have 9x - 4x = 5x for the middle term.

anonymous · Answer

You can always check your factorization by foiling it out to see if you got what you started with.
$$(3x+1)(4x-3) = 12x^2 -9x + 4x -3 = 12x^2 -5x -3$$

anonymous · Answer

Which isn't right.

anonymous · Answer

whats not right??

anonymous · Answer

(3x+1)(4x-3) isn't the factored form of $ 12x^2+5x−3$