Question

pls give me the steps to find the slope of tangent for 5x^2-2 x=5

Answer 1

we hav the equation, y=5x^2-2x-5;

dy/dx,will giv u the slope @ (x,y) and so we hav ,
dy/dx=10x-2

Answer 2

so the slope = 10x-2 @ the point (x,y).

Answer 3

the answer isnt right bracket

Answer 4

your equation is 5x^2- 2 , differetian it gives the slop
d/dx [5x^2-2] = 10x >>> at x = 5 slop = 50

Answer 5

slope**

Answer 6

yoyo, sorry i was misled by u not putting a comma after the equation...please be carefull , cheers :)

Answer 7

that is fine thank u soo much for ur help