Question

6x^2/6x^2+9+3 times 6x+3/2x

Answer 1

hi what is on the bottom? is it \[6x^2/(6x^2+9) +3\]

Answer 2

nope just 6x^2+9+3

Answer 3

all that on the bottom? so \[6x^2/(6x^2+12)\]
or is it
\[6x^2/6x^2\]+12

Answer 4

its 2 fractions that x the others

Answer 5

ok so I believe the equation looks like this
\[6x^2/(6x^2 +12) * (6x+3)/2x\]
simplify the first term by dividing by 6
\[x^2/(x^2+2)\]
then multiply
\[(6x^3+3x^2)/(2x^3+4x)\]
divide by x and the final product should be
\[(6x^2+3x)/(2x^2+4)\]