OpenStudy (anonymous):

6x^2/6x^2+9+3 times 6x+3/2x

6 years ago
OpenStudy (anonymous):

hi what is on the bottom? is it \[6x^2/(6x^2+9) +3\]

6 years ago
OpenStudy (anonymous):

nope just 6x^2+9+3

6 years ago
OpenStudy (anonymous):

all that on the bottom? so \[6x^2/(6x^2+12)\] or is it \[6x^2/6x^2\]+12

6 years ago
OpenStudy (anonymous):

its 2 fractions that x the others

6 years ago
OpenStudy (anonymous):

ok so I believe the equation looks like this \[6x^2/(6x^2 +12) * (6x+3)/2x\] simplify the first term by dividing by 6 \[x^2/(x^2+2)\] then multiply \[(6x^3+3x^2)/(2x^3+4x)\] divide by x and the final product should be \[(6x^2+3x)/(2x^2+4)\]

6 years ago
Similar Questions: