Simplify: (x^3-8) ok i know it simplifies to (x-2)(x^2+2x+4) but i don't know why
just memorise it lol
you can expand to see that its correct,
factors? okay you know that x=2 is one zero of x^3-8=0 so a factor of x^3-8 is x-2 we can use x-2 to find the other factor(s) 2| 1 0 0 -8 | 2 4 8 _________________________ 1 2 4 | 0 so another factor is 1x^2+2x+4
but things like that u just have to memorise
:|
It's the difference of cubes. And no, don't memorize it. Not really worth wasting brain space on. Just know that there is a formula for it, know what it's called, and how to identify it. Then you can look up the formula when you need to. Or you can (as myininaya did) use synthetic division.
where myininaya's post?
i cant remember the formula for factoring difference and sum of cubes so i always find one zero if f(x)=0 then use it to find the other factor(s)
i know how they get the first bracket but not the 2nd
do you know snytheic of long divison?
why not memorise lols , its just like the difference of sqaures formula. some people dont know polynomial division ( I know in high schools in Australia you dont get taught polynomial division if you are in the basic calculus subject ) and even if you do its not worth the time manually doing it
or*
i like to know how formulas are derived
a^3-b^3 = (a-b)(a^2 +ab +b^2) easy as to remember
a^3-b^3 = (a-b)(a^2 +ab +b^2) easy as to remember
yes myininaya i know how to do synthetic division i just saw your post sorry
lol but more fun to divide! :)
divide and conquer!
then for the sum of cubes you change the a-b to a+b , and you swap the sign on ab
lol i see what your sayin elecenginer
you always know the signs in first bracket ( because they come from whether its sum or difference ) , then u make sure u have different sign on the ab term
i remember the basic form i just have to do it to remember where to put the plus and minus (i always have to find one zero to help me set the factors up
lol ok thanks so much guys
np
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