Question

Solve for w.
w^2-5w-36=0
enter answer in this format __,__

Answer 1

the "format" there doesnt convey any meaningful information; that is simply the authors construction which is undefined outside of his parameters

Answer 2

but given that; we need to factor the quadratic equation to see it easier

Answer 3

x^2 + (b+c)x + (bc) is the format for this equation; so we need to find 2 numbers ; b and c that make this true:

bc = -36
b+c = -5

Answer 4

I can see from experience that -9 and +4 make this true

-9(4) = -36

-9+4 = -5

Answer 5

i thought i just have to figure out what (w)is

Answer 6

so lets split this into: (x+b) (x+c) = 0

(x-9) (x+4) = 0

Another thing to keep in mind is that anything times 0 = 0; so there are 2 ways to get this to = 0;

when x=9 we have: (9-9)(9+4)=0 and that is true

when x=-4 we have: (-4-9)(-4+4) = 0 which is true

Answer 7

yes, and this is how you do it .... but I used 'x' instead of 'w' just by instinct

Answer 8

so 9,-4

Answer 9

so; w = x in this .... its just a name, not a value.

x=9 and x=-4 are your values

yes, but I have no idea what the 'format' means so ill leave that for you to decipher ;)

Answer 10

thank you (:

Answer 11

youre welcome ☺