Question

solve for c.
c^2+7c+12=0

Answer 1

c^2+4c+3c+12=0
c(c+4)+3(c+4)=0
(c+3)(c+4)=0
c=-3 and -4

Answer 2

it was coreect

Answer 3

same steps; trying to find a value for, in this case i spose:

c^2 +(a+b)c + (ab)

ab = 12
a+b = 7

4 and 3 good;

(c+4)(c+3); when c=-4 this = 0; when c=-3, this also =0