Question

Find X=?

Answer 1

More info?

Answer 2

yup

Answer 3

See the attachment :)

Answer 4

Okay I'ma take a guess. 1/3 and 2/x (fraction form)

Cross multiply 2 * 3 = 6
1 * x = 1x
6 =1x

6 divided by 1 = 6

So....6.

Answer 5

i dont think there are any properties which will help in finding x..the triangles are not similar...

Answer 6

I didn't do the triangle... I did the square thingy...

Answer 7

I know that's why i couldn't solve it...O.o
Idk wht has happened to me 2day but I've solved all the problems....(besides this) O.o :P

Answer 8

what square? and can u plssss explain better?

Answer 9

I still say 6.

Answer 10

The tilty thing CDAE?

Answer 11

CDEA or whatever.

Answer 12

are u sure ur lengths are correct angela? this may be a wrong question...

Answer 13

I still say 6.

Answer 14

yea..i drew it exactly as in my book...i think it has to do with cos theorem

Answer 15

k...its good..use cosine rule...with angle B

Answer 16

\[cosB=\frac{3^2+4^2-2^2}{2\times3\times4}=\frac{4^2+7^2-x^2}{2\times4\times7}\]
Find x.

Answer 17

understood?

Answer 18

its x=4. :) hope u get it...

Answer 19

i know the formula but the problem is that i don't know cosB?

Answer 20

I STILL SAY 6!

Answer 21

yah...angela u dont need to know cosB...use cosine rule in triangle BDE and then find cosB and using this info use cosine rule again in triangle ABC. Find x then. see my equation few posts bfore.. :)

Answer 22

@lovelesstime x=4 not 6.

Answer 23

don't we have to unknown in there?

Answer 24

from triangle BDE find cosB using cosine rule...
from triangle ABC use the found value of cosB to find x using cosine rule..

Answer 25

got it?

Answer 26

Oh...right i got it :):):)
Thnx a loooooooooot :):)
(sorry but my conn. sucks)