Question

when 8x^-3-64x is factored completely, one of the factors is?

Answer 1

=8x(x^2-8)
so either 8x or x^2 -8

Answer 2

thanks , man you're good at this lol good job(:
i wish i had that capability

Answer 3

just think of what they have in common
both 8 and 64 are divisible by 8
and they both have an x

anyway thanks

Answer 4

so how you get x^2-8?

Answer 5

by dividing each term by 8x
\[\frac{8x^{3}}{8x} = x^{2}\]
\[\frac{64x}{8x} = 8\]