Question

log 7^(x+2) = -2

Answer 1

is this log of base 10 or 7, weezie?

Answer 2

if it is \[log_7(7^{x+2})=-2\]
solve
\[x+2=-2\] because
\[log_7(7^y)=y\]

Answer 3

if it is \[log_{10}(7^{x+2})=-2\]
this means
\[10^{-2}=7^{x+2}\] requires more work

Answer 4

log base 7

Answer 5

did you get it weezie?

Answer 6

log 7^(x + 2) = -2

Answer 7

log(base7)7^(x+2) = -2 log(base7)7^Y = Y=-2

then your Y= x+2 so that here Y=-2

x+2 =-2
x=-4

Answer 8

why is there two sevens.....

Answer 9

the one there is the base 7,and the other one is 7^(x+2)

Answer 10

ok

Answer 11

did you understand the idea there?

Answer 12

no sorry I did not...

Answer 13

what is always true is that
\[log_b(b^{whatever})=whatever\]

Answer 14

oh ok that is better..

Answer 15

that is much better ..lol

Answer 16

whew. so the problem is really easy since the left hand side is just x+2

Answer 17

or
log(base a)a^(y)=y

Answer 18

log(base a)a^(z)=z its still z
log(base a)a^(x)=x its still x
log(base a)a^(y)=y
log(base7)7^(x+2) = (x+2) is it better now?

Answer 19

talk to me weezie...lol

Answer 20

yes thank you very much

Answer 21

sure? i can explain more

Answer 22

log(base7)7^(x+2) = (x+2) then
log(base7)7^(x+2) = -2 will be equal to......
(x+2) = -2 now u can solve for x
x= -2-2
x= 4

Answer 23

im so sorry its x=-4...kind of sleepy now late in bed lol...

Answer 24

oh that is great...

Answer 25

ok weezie,, good luck now....lol

Answer 26

that way is better

Answer 27

alright.........yeheyyyyyyyyyyyyyyyyy........

Answer 28

lol thanks so much....

Answer 29

ok, take care now im going to bed now ,,,,good nyt here lol ..

Answer 30

k nite nite...you too

Answer 31

k,, thnkx