Question

y varies directly as the square of x. when x=3, y=8. Find y when x=2

Answer 1

sorry what;s the answer ?

Answer 2

f(x) is \[y=\sqrt{x}\]

Answer 3

Sorry I lost it :(

Answer 4

no...it should be done in this way....

Answer 5

\[y=k{x^2}\]
when x=3, y=8
8=k*3^2
k=8/9

y=8x^2/9
when x=2
y=8*2^2/9=32/9