Question

A model for a company’s revenue is r=-15p^2+300p+12,000 ,where p is the price in dollars of the company’s product. What price will maximize revenue?

Answer 1

\[r=-15p^2+300p+12,000\]

Answer 2

magic formula is
\[-\frac{b}{2a}\]

Answer 3

in this case a = -15, b = 300 so
\[-\frac{b}{2a}=\frac{300}{30}=10\]

Answer 4

replace p by 10 and you win.

\[-15(10)^2+300\times 10+1200=2700\]