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find a function f that satisfies the condition f''(x) = x^2, f'(0) = , f(0) = 3 this is antiderivatives and indefinite integrals (ie. applications of it)
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f''(x)=x^2 implies that f(x)= x^4/12+Ax+B f(0)=3 implies that B=3 f'(0)= gap implies A=gap so the function is f(x)=x^4/12 +gap x+3
:S huh?
I guess you missed out something?
f'(0) =
6
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ok than gap=6 :-)
can u write it out w/ out the gap because i still dont see it
f''(x)=x^2 implies that f(x)= x^4/12+Ax+B f(0)=3 implies that B=3 f'(0)=6 implies A=6 so the function is f(x)=x^4/12 +6x+3
if something is not clear just ask
oh ok i get it now lol...thank you sorry my eyes are so blurry
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