Question

Solve by using quadratic formula: 5x^2+x=5

Answer 1

We would like for this equation to be in the form
\[ax^2 + bx + c = 0.\]
That was we can see what a, b, and c are.
First subtract 5 from both sides,
\[5x^2+x-5=0\]
Sometimes it helps to see the coefficient of 1,
\[5x^2+1x-5=0\]
Now a= 5, b = 1, c = -5. Plugging these values into the quadratic formula,
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
\[=\frac{-(1) \pm \sqrt{(1)^2 - 4(1)(-5)}}{2(5)}\]
\[=\frac{-1 \pm \sqrt{1 +20}}{10}\]
\[=\frac{-1 \pm \sqrt{21}}{10}\]
Now the square root of 21 does not simplify, so this is a final answer.

Answer 2

A= 5

Answer 3

not 1

Answer 4

oops

Answer 5

Thanks