Mathematics
OpenStudy (anonymous):

8 years ago
OpenStudy (anonymous):

is it just -1 +- the square root of 101/10?

8 years ago
OpenStudy (anonymous):

5x^2+x-5=0 ax^2+bx+c=0 then $x=-b \pm \sqrt{b^2 -4ac} \div$

8 years ago
OpenStudy (anonymous):

Rewrite: $5x^2+x-5=0$ Quadratic formula: $x=(-b \pm \sqrt{b^2-4ac)})/2$ So x = (1/2)(-1 +/- sqrt(1-4times1times(-5)) = (1/2)(-1+/- sqrt21)

8 years ago
OpenStudy (anonymous):

Yeah i get that but what after that??

8 years ago
OpenStudy (anonymous):

div 2a

8 years ago
OpenStudy (anonymous):

Yes i know thats too far into decimals to work with

8 years ago
OpenStudy (anonymous):

x=-1/2 +/- (1/2)sqrt21=-0.5+/- 2.29 (from calculator) x= -2.79 or +1.79

8 years ago
OpenStudy (anonymous):

yes right

8 years ago
OpenStudy (anonymous):

Something's wrong. These solutions don't satisfy the original equation. Back soon.

8 years ago
OpenStudy (anonymous):

I forgot to divide by 2a = 10

8 years ago
OpenStudy (anonymous):

I know thats what im saying

8 years ago
OpenStudy (anonymous):

So sorry - carelessness on my part. Here we go again: $x=(-1\pm \sqrt{1-4\times5\times(-5)})/10$ $x=(-1\pm \sqrt{101})\div10$ x = (-1 +/- 10.0499)/10 x = -1.10499 or 0.90499

8 years ago
OpenStudy (anonymous):

Still not right!

8 years ago
OpenStudy (cruffo):

guyc, I got the same answer: $\frac{-1 \pm \sqrt{101}}{10}$ Now the square root of 101 does not simplify since 101 is prime, so this is a final answer.

8 years ago
OpenStudy (anonymous):

Yes, I agree with cruffo. Incidentally, my decimal answers do in fact satisfy the original equation. I do hope I didn't confuse you with my ramblings!

8 years ago