Mathematics
OpenStudy (anonymous):

rationalize the denominator sqrt 6/sqrt 3 + sqrt 5

OpenStudy (anonymous):

is sqrt 3 + sqrt 5 the denominator?

OpenStudy (anonymous):

yes

OpenStudy (nikita2):

you should multiple up and down on sqrt 3 - sqrt 5, and use formula (a-b)(a+b) = a^2-b^2

OpenStudy (nikita2):

So you will have (sqrt 6)(sqrt 3 - sqrt 5)/(3 - 5)

OpenStudy (anonymous):

we do what is called multiplying by the conjugate the conjugate of a+b is a-b. this is especially useful for imaginary numbers. in your case, as nikita pointed out, $\frac{\sqrt{6}}{\sqrt{3}+\sqrt{5}} = \frac{\sqrt{6} \times (\sqrt{3}-\sqrt{5})}{(\sqrt{3}+\sqrt{5})\times (\sqrt{3}-\sqrt{5})} = \frac{\sqrt{6} \times (\sqrt{3}-\sqrt{5})}{3-5}$

OpenStudy (anonymous):

ok thanks you guys are great

OpenStudy (anonymous):

you are welcome