Question

y=4-sqrt{3-x}

Answer 1

what about it?

Answer 2

how do I solve it? When it is 4- the square root of 3-x

Answer 3

sorry I disappeared

Answer 4

it's ok i did too

Answer 5

it's the same square root function stuff.

Answer 6

Are you trying to solve for Y? Remember that the square root cannot be negative inside the radical. so how big can x be? ---> 3-x>=0

Answer 7

I'm trying to find the domain.

Answer 8

Yep. Greater than or equal to 0

Answer 9

I just don't know what to do with the 4-

Answer 10

the domain is only focusing on what your x values can do.

Answer 11

so what's outside of the square root sign doesn't really matter?

Answer 12

I'm only focusing on what's on the inside?

Answer 13

to the domain, it does not matter.

Answer 14

Yes. In these problems they want you to see that the square root in general limits what values x can have, when an x is inside it.

Answer 15

The square root places boundaries on what numbers x can be.

Answer 16

in this problem x cannot be greater than 3, because you cannot have a negative value inside the "radical"

Answer 17

3-x>=0

so x can be anything less than three, including all negative numbers because 3-(-5) = 3+5 = 8, and that is greater than 0 obviously.

Answer 18

Okidoke. It all makes sense to me now. I'm pretty sure I got this.

Answer 19

haha. Sorry went on too much. You could have told me shut up 5 lines back. :)