y=4-sqrt{3-x}

8 years agowhat about it?

8 years agohow do I solve it? When it is 4- the square root of 3-x

8 years agosorry I disappeared

8 years agoit's ok i did too

8 years agoit's the same square root function stuff.

8 years agoAre you trying to solve for Y? Remember that the square root cannot be negative inside the radical. so how big can x be? ---> 3-x>=0

8 years agoI'm trying to find the domain.

8 years agoYep. Greater than or equal to 0

8 years agoI just don't know what to do with the 4-

8 years agothe domain is only focusing on what your x values can do.

8 years agoso what's outside of the square root sign doesn't really matter?

8 years agoI'm only focusing on what's on the inside?

8 years agoto the domain, it does not matter.

8 years agoYes. In these problems they want you to see that the square root in general limits what values x can have, when an x is inside it.

8 years agoThe square root places boundaries on what numbers x can be.

8 years agoin this problem x cannot be greater than 3, because you cannot have a negative value inside the "radical"

8 years ago3-x>=0 so x can be anything less than three, including all negative numbers because 3-(-5) = 3+5 = 8, and that is greater than 0 obviously.

8 years agoOkidoke. It all makes sense to me now. I'm pretty sure I got this.

8 years agohaha. Sorry went on too much. You could have told me shut up 5 lines back. :)

8 years ago