y=4-sqrt{3-x}

what about it?

how do I solve it? When it is 4- the square root of 3-x

sorry I disappeared

it's ok i did too

it's the same square root function stuff.

Are you trying to solve for Y? Remember that the square root cannot be negative inside the radical. so how big can x be? ---> 3-x>=0

I'm trying to find the domain.

Yep. Greater than or equal to 0

I just don't know what to do with the 4-

the domain is only focusing on what your x values can do.

so what's outside of the square root sign doesn't really matter?

I'm only focusing on what's on the inside?

to the domain, it does not matter.

Yes. In these problems they want you to see that the square root in general limits what values x can have, when an x is inside it.

The square root places boundaries on what numbers x can be.

in this problem x cannot be greater than 3, because you cannot have a negative value inside the "radical"

3-x>=0 so x can be anything less than three, including all negative numbers because 3-(-5) = 3+5 = 8, and that is greater than 0 obviously.

Okidoke. It all makes sense to me now. I'm pretty sure I got this.

haha. Sorry went on too much. You could have told me shut up 5 lines back. :)

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