Mathematics
OpenStudy (anonymous):

y=4-sqrt{3-x}

OpenStudy (anonymous):

OpenStudy (anonymous):

how do I solve it? When it is 4- the square root of 3-x

OpenStudy (anonymous):

sorry I disappeared

OpenStudy (anonymous):

it's ok i did too

OpenStudy (anonymous):

it's the same square root function stuff.

OpenStudy (anonymous):

Are you trying to solve for Y? Remember that the square root cannot be negative inside the radical. so how big can x be? ---> 3-x>=0

OpenStudy (anonymous):

I'm trying to find the domain.

OpenStudy (anonymous):

Yep. Greater than or equal to 0

OpenStudy (anonymous):

I just don't know what to do with the 4-

OpenStudy (anonymous):

the domain is only focusing on what your x values can do.

OpenStudy (anonymous):

so what's outside of the square root sign doesn't really matter?

OpenStudy (anonymous):

I'm only focusing on what's on the inside?

OpenStudy (anonymous):

to the domain, it does not matter.

OpenStudy (anonymous):

Yes. In these problems they want you to see that the square root in general limits what values x can have, when an x is inside it.

OpenStudy (anonymous):

The square root places boundaries on what numbers x can be.

OpenStudy (anonymous):

in this problem x cannot be greater than 3, because you cannot have a negative value inside the "radical"

OpenStudy (anonymous):

3-x>=0 so x can be anything less than three, including all negative numbers because 3-(-5) = 3+5 = 8, and that is greater than 0 obviously.

OpenStudy (anonymous):

Okidoke. It all makes sense to me now. I'm pretty sure I got this.

OpenStudy (anonymous):

haha. Sorry went on too much. You could have told me shut up 5 lines back. :)

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