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OpenStudy (anonymous):
how do you take out the natural log? like in this case... 1=lnx i completely forgot how to do this...
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OpenStudy (nikita2):
use the rule e^ln(x) = x
OpenStudy (anonymous):
so in that 1=lnx, can i just do e^1=e^lnx and then solve?
OpenStudy (nikita2):
x = e ? )
OpenStudy (anonymous):
thanks!
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