Ask
your own question, for FREE!
Mathematics
43 Online
Use implicit differentiation to find dy/dx given that x^3y-sin2y=4+y^3
Still Need Help?
Join the QuestionCove community and study together with friends!
(x^3y)'=3dy/dx x^(3y-1) (-sin2y)'=-2dy/dx cos2y (4+y^3)'=3dy/dx y^2 factor out dy/dx and you will have your answer
\[x^3y -sin(2y)=4+y^3\] \[3x^2y+x^3y'-2\cos(y)y'=3y^2y'\] \[3x^2y=3y^2y'+2\cos(2y)y'-x^3y'\] \[3x^2y=y'(3y^2+2\cos(2y)-x^3)\] \[\frac{3x^2y}{3y^2+2\cos(2y)-x^3}=y'\]
check the algebra!
thats what i have satellite thanks :D
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
forgetmylife:
Only the real understand ud83eudd26ud83cudffdu2642ufe0f I'm tired. Tired of the constancy, the constancy of judgment.
rishavraj:
Just trying to find a friend. We met on openstudy, her nickname on there was something "tarantula".
Subshilava:
Which sentence follows correct grammatical conventions? ) u2022 The crow in that bush squawk loudly at the hawks.
9 hours ago
2 Replies
1 Medal
54 minutes ago
4 Replies
0 Medals
1 day ago
4 Replies
3 Medals