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OpenStudy (anonymous):
The value of 1/4+1/4.3+1/4.3^2+1/4.3^3=?
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OpenStudy (anonymous):
1/4(1+1/3+1/3^2+1/3^3) 1/4(1-(1/3)^4)*1 ---------------- 1-1/3
OpenStudy (anonymous):
is this an infinite series or finite? that is \[\frac{1}{4}(1+\frac{1}{3}+\frac{1}{3^2} +\frac{1}{3^3}...)\]
OpenStudy (anonymous):
or is it just the one you wrote?
OpenStudy (anonymous):
could you plz explain how you get 1/3
OpenStudy (anonymous):
finite geometric series
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OpenStudy (anonymous):
1/3 is the common ratio
OpenStudy (anonymous):
it is not \[\frac{1}{3}\] if it is just the terms you wrote.
OpenStudy (anonymous):
its 1/4 + 1/4.3, how it becomes 1+1/3
OpenStudy (anonymous):
1/4 is common
OpenStudy (anonymous):
oh is it 4.3 i took it 4*3???
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OpenStudy (anonymous):
problem is odd if it is exactly what you wrote, then you need a calculator. can you post a picture of the original problem?
OpenStudy (anonymous):
Yes, its 4.3
OpenStudy (anonymous):
yeah, otherwise its simple one
OpenStudy (anonymous):
then satellite is right. u just need a calculator
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