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OpenStudy (anonymous):
-x^2-x+2 find the vertex
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OpenStudy (anonymous):
i no its -b/2a
OpenStudy (anonymous):
so i did -1/2(-1)
OpenStudy (anonymous):
i got 1/2
OpenStudy (anonymous):
a = -1, b = -1 and vertex = -b/2a so plug the values in
OpenStudy (anonymous):
correct
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OpenStudy (anonymous):
oops its -(-1) / -2 = -1/2
OpenStudy (anonymous):
sorry!!
OpenStudy (anonymous):
you have a double negative -(-1) = +1
OpenStudy (anonymous):
its -1/2
OpenStudy (anonymous):
here is another one -x^2-x+1
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OpenStudy (anonymous):
get the same -1/2
OpenStudy (anonymous):
whats the second half though
OpenStudy (anonymous):
sorry ? pardon ??
OpenStudy (anonymous):
like the first point is -1/2 but i need another one bc the vertex makes up two points
OpenStudy (radar):
the -1/2 is the x in P(-1/2,y) the other point can be obtained from the equation, substitute the -1/2 for x and solve for y.
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OpenStudy (radar):
* change to read: the y value can be obtained from the equation, substitute the -1/2 for x and solve.
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