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Mathematics 38 Online
OpenStudy (anonymous):

-x^2-x+2 find the vertex

OpenStudy (anonymous):

i no its -b/2a

OpenStudy (anonymous):

so i did -1/2(-1)

OpenStudy (anonymous):

i got 1/2

OpenStudy (anonymous):

a = -1, b = -1 and vertex = -b/2a so plug the values in

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

oops its -(-1) / -2 = -1/2

OpenStudy (anonymous):

sorry!!

OpenStudy (anonymous):

you have a double negative -(-1) = +1

OpenStudy (anonymous):

its -1/2

OpenStudy (anonymous):

here is another one -x^2-x+1

OpenStudy (anonymous):

get the same -1/2

OpenStudy (anonymous):

whats the second half though

OpenStudy (anonymous):

sorry ? pardon ??

OpenStudy (anonymous):

like the first point is -1/2 but i need another one bc the vertex makes up two points

OpenStudy (radar):

the -1/2 is the x in P(-1/2,y) the other point can be obtained from the equation, substitute the -1/2 for x and solve for y.

OpenStudy (radar):

* change to read: the y value can be obtained from the equation, substitute the -1/2 for x and solve.

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