Question

find the vertex y-int x-int

-x^2+6x-5

Answer 1

set y = 0 to obtain x intercept
set x=0 to obtain y intercept

Answer 2

solve by factoring
\[-x^2+6x-5=0\]
\[x^2-6x+5=0\]
\[(x-1)(x-5)=0\]
\[x-1=0\]
\[x=1\]
\[x-5=0\]
\[x=5\] your x - intercepts are 1 and 5

Answer 3

whats the vertex

Answer 4

magic formula is
\[-\frac{b}{2a}=-\frac{6}{2\times -1}=3\]

Answer 5

first coordinate of vertex is 3. second is what you get when you replace x by 3