Mathematics
OpenStudy (anonymous):

find the vertex y-int x-int -x^2+6x-5

set y = 0 to obtain x intercept set x=0 to obtain y intercept

OpenStudy (anonymous):

solve by factoring $-x^2+6x-5=0$ $x^2-6x+5=0$ $(x-1)(x-5)=0$ $x-1=0$ $x=1$ $x-5=0$ $x=5$ your x - intercepts are 1 and 5

OpenStudy (anonymous):

whats the vertex

OpenStudy (anonymous):

magic formula is $-\frac{b}{2a}=-\frac{6}{2\times -1}=3$

OpenStudy (anonymous):

first coordinate of vertex is 3. second is what you get when you replace x by 3

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