find the slope of a line perpendicular to the line containing the points (3,-1) and (-7,2).

I would find the slope of the line passing thru the those two points. Slope symbol is m and it is equal to:\[m=\Delta y/\Delta x\] or\[m= (y ^{2}-y ^{1})/(x ^{2}-x ^{1})=(2-(-1))/(-7-3)=3/-10=-3/10\] A line that is perpendicular to this line will have the negative reciprocal of this slope. That would be 10/3 so the slope for the line perpendicular to the line containing the points (3,-1) and (-7,2) has a slope of 10/3

slope of line containing points (3,-1) and (-7,2) is (2+1)/(-7-3)=-3/10 since we know that if two lines are perpendicular then product of their slope is -1. thus, slope of line perpendicular to the line containing the points (3,-1) and (-7,2) is 10/3.

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