find the slope of a line perpendicular to the line containing the points (3,-1) and (-7,2).

Question

radar · Answer

I would find the slope of the line passing thru the those two points.
  Slope symbol is m and it is equal to:$$m=\Delta y/\Delta x$$ or$$m= (y ^{2}-y ^{1})/(x ^{2}-x ^{1})=(2-(-1))/(-7-3)=3/-10=-3/10$$
 A line that is perpendicular to this line will have the negative reciprocal of this slope.

That would be 10/3  so the slope for the line perpendicular to the line containing the points (3,-1) and (-7,2) has a slope of 10/3

anonymous · Answer

slope of line containing points  (3,-1) and (-7,2) is  (2+1)/(-7-3)=-3/10

since we know that if two lines are perpendicular then product of their slope is -1.

thus, slope of line perpendicular to the line containing the points (3,-1) and (-7,2) is 10/3.