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OpenStudy (anonymous):
Hey !:) how would you find the integral of a function with no specific u value..such as...?
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OpenStudy (anonymous):
\[\int\limits_{?}^{?} x ^{3}-6x-20divx+5\]
OpenStudy (anonymous):
\[∫??x3−6x−20 \div x+5\]
OpenStudy (anonymous):
Just rewrite it as: \[\int\limits x^3-6x-20x^{-1}+5 dx\] Integrate term by term.
OpenStudy (anonymous):
can u show more steps..i always get stcuk with integration by parts...:(
OpenStudy (anonymous):
so it wud b..x^3/3-6x^2/2+5x +c
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OpenStudy (anonymous):
Well if you have 20/x then it would be 20ln|x| because you know that the derivative of ln(x)=1/x so the integral of 1/x is ln|x| xP
OpenStudy (anonymous):
But the rest is right :)
OpenStudy (anonymous):
so the deiv rules apply to integral rules too??
OpenStudy (anonymous):
They work in reverse so if you have the derivative of x is 1. But the integral of 1 is x. They are inverse operations.
OpenStudy (anonymous):
ohh right...thanks a lotttt
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