Question

Hey !:)
how would you find the integral of a function with no specific u value..such as...?

Answer 1

\[\int\limits_{?}^{?} x ^{3}-6x-20divx+5\]

Answer 2

\[∫??x3−6x−20 \div x+5\]

Answer 3

Just rewrite it as:
\[\int\limits x^3-6x-20x^{-1}+5 dx\]
Integrate term by term.

Answer 4

can u show more steps..i always get stcuk with integration by parts...:(

Answer 5

so it wud b..x^3/3-6x^2/2+5x +c

Answer 6

Well if you have 20/x then it would be 20ln|x| because you know that the derivative of ln(x)=1/x so the integral of 1/x is ln|x| xP

Answer 7

But the rest is right :)

Answer 8

so the deiv rules apply to integral rules too??

Answer 9

They work in reverse so if you have the derivative of x is 1. But the integral of 1 is x. They are inverse operations.

Answer 10

ohh right...thanks a lotttt