Hey !:)
how would you find the integral of a function with no specific u value..such as...?

Question

anonymous · Answer

$$\int\limits_{?}^{?} x ^{3}-6x-20divx+5$$

anonymous · Answer

$$∫??x3−6x−20 \div x+5$$

anonymous · Answer

Just rewrite it as:
$$\int\limits x^3-6x-20x^{-1}+5 dx$$
Integrate term by term.

anonymous · Answer

can u show more steps..i always get stcuk with integration by parts...:(

anonymous · Answer

so it wud b..x^3/3-6x^2/2+5x +c

anonymous · Answer

Well if you have 20/x then it would be 20ln|x| because you know that the derivative of ln(x)=1/x so the integral of 1/x is ln|x| xP

anonymous · Answer

But the rest is right :)

anonymous · Answer

so the deiv rules apply to integral rules too??

anonymous · Answer

They work in reverse so if you have the derivative of x is 1. But the integral of 1 is x. They are inverse operations.

anonymous · Answer

ohh right...thanks a lotttt