Question

Given the linear equation y= 1/3x-3, find the y-coordinates of the points (-6, ), (-3, ), and (6, ). Please show all of your work

Answer 1

y= (1/3x) - 3



Put x = -6

y = (1/3)*(-6) - 3 = -2-3 = -5

Point will be (-6, -5).



Put x = -3

y = (1/3)*(-3) - 3 = -1-3 = -4

Point will be (-3, -4).



Put x = 6

y = (1/3)*(6) - 3 = 2-3 = -1

Point will be (6, -1).