Question

Solve by factoring x^2-8x-9=0

Answer 1

Tiny - Try (x-9)*(x+1)

Answer 2

how did you do that?

Answer 3

ok. step by step. you have an x^2 to factor, so you know that you will have to split that into 2 different x's in different ( ). That's the easy step. Next, look at your last number (-9) and think about numbers that are factors of 9 (3 X 3 comes to mind first for me, although in ths case, it doesn't work). Here's why - you need the factors of -9 to add up to the number that you get when adding the middle digit by the factors. So, I figured other factors of nine were 1 and 9. A -9 and a +1 add up to -8, which is the middle digit we're looking for.

Answer 4

okay thank you so much

Answer 5

yw!

Answer 6

nobody is getting this right please help:
\[2x ^{2}+3x=0\]