Question

Solve the questions in the attachment and be suure to show work and provide an explanation why.

Answer 1

SOMEONE HEL

Answer 2

P

Answer 3

how in the heck do you do those?

Answer 4

you re not hlping

Answer 5

you're not trying

Answer 6

YEA I AM

Answer 7

oh good

Answer 8

For the second one, angle ADB is equal to angle AEB because of inscribed angle theorem. and then angle ACB is twice angle AEB because of angle at the center theorem.

Answer 9

CANyou show me the ligt work for all f them

Answer 10

and explan why

Answer 11

I didnt do the actual proof out. but if you look up the two theorems, I am sure you can find the proof clearly written somewhere.

Answer 12

and that means for the first one, angle ADB is 1/2 of angle ACB based on the same two theorems

Answer 13

yu have t show me themath part2

Answer 14

okay, i remember this stuff now. i do not have a scanner so I cant write it all out, but I can try to explain it more clearly

Answer 15

and you can write math out... right?
there isnt math to it. its literally circle theorem.

Answer 16

I can try to explain this for each. Look at the first picture.

Answer 17

the proof for the angle at the center part is : http://www.mathsrevision.net/gcse/pages.php?page=13 just scroll down. if you follow the same process you can get it

Answer 18

see if this is what you needed..

Answer 19

http://www.benjamin-mills.com/maths/Year11/circle-theorems-proof.pdf

the first two pages explain the two theorems I was using.

Answer 20

Just so you know, the first three are wrong.

Answer 21

oh wel said not sure if they are right.. what si the right answer? my daughter just finished this work in school so she was helping me

Answer 22

well i gotta go. i will be back tomorrow to get help with my problems..lolhave a good night and thanks

Answer 23

hry ally cat

Answer 24

for the first one, assuming AC=CB and C is the center, such at that ACB is an isosceles triangle, extend a line from C to D, this should also be equal to AC and CB. the angle CAD=angleCDA because ACD is an isosceles triangle. .... more to come in a sec

Answer 25

which we put is a triangle. thats not right?

Answer 26

technically it is a triangle, but shes is looking for the ANGLE of ADB.

Answer 27

not on the first one..didnt it just ask what it is? i didnt know it asked for an angle too...lol same for the second one..it asked what it was, so i didnt put the angle.. lol

Answer 28

so about the third one?

Answer 29

the little < symbole means angle.

Answer 30

<DCE = 2*124=248

Answer 31

for the first one, <ADB= (1/2)*150 = 75 degrees

Answer 32

second one, <ACB = 2*66=132 degrees
and <ADB = <AEB = 66 degrees

Answer 33

already did the third one,

so the fourth is = 180-2*25=180-50=130 degrees

Answer 34

along with the those questions , can you pu a xplaiation for each 1

Answer 35

have you been taught the circle theorems?

Answer 36

can you just explain it

Answer 37

the angle theorems take a lot of explaining, which i am not the best at doing.

Answer 38

ugh .... just explain how you got each answer

Answer 39

you need to knwo the angle theorem to get the answer. its that fluttering simple. I gave you the answers, now go look up the theorem and quit spamming the boards with your constant comments. I am trying to help you and all you are being is rude and inconsiderate.

Answer 40

explain how you got each answer ok???

Answer 41

that simple

Answer 42

the first one is based on the circle theorem angle at the center. you know BASED ON THE THEOREM, that the angle ACB is twice angle ACB... done

Answer 43

that is not an expanation xplain t step by step (theorm)

Answer 44

GO LOOK UP THE THEOREM. I GAVE YOU THE LINK ALREADY. READ IT!

Answer 45

just ixplain it