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Mathematics 21 Online
OpenStudy (anonymous):

5x(3x^2-5)-2(3x^2-5)=(5x-2)*(3x^2-5) how do you get this answer?

OpenStudy (anonymous):

You simplify each side and they should equal each other.

OpenStudy (anonymous):

Yep, it does. :)

OpenStudy (anonymous):

how do you get the 5x-2 in the answer though when it says 5x(3x^2-5)

OpenStudy (anonymous):

??? If you do each side independently then they turn out to be the same thing, you don't need to make them look like each other though it is possible by distributing and then going backwards by factoring.

OpenStudy (anonymous):

15x^3-31x^2+10=15x^3-31x^2+10

OpenStudy (anonymous):

how do you get 5x-2? where does the 2 come from?

OpenStudy (anonymous):

From the answer? Or from the LHS?

OpenStudy (anonymous):

from the answer.

OpenStudy (anonymous):

Do everything backwards from the answer on the RHS. Your asking if this is a true statement and/or to prove it?

OpenStudy (anonymous):

Do you want me to show you step by step what I did?

OpenStudy (anonymous):

yes please

OpenStudy (anonymous):

LHS: 5x(3x^2-5)-2(3x^2-5) Distribute 5x and -2 15x^3-25x^2-6x^2+10 Combine like terms 15x^3-31x^2+10 RHS: (5x-2)*(3x^2-5) Foil 15x^3-25x-6x^2+10 Combine like terms 15x^3-31x^2+10

OpenStudy (anonymous):

Do you understand?

OpenStudy (anonymous):

yess now i do, thank you ( :

OpenStudy (anonymous):

Welcome :)

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