How many hours is 2/3 of 1 hour and 36 minutes? PLEASE Help me answer it, i feel like im close...yet so far away!

1 hour and 36 minutes is 96 minutes, agreed?

corrrrrrect! and I get pretty stuck after that!

okay. what is one-third of 96?

okay when I type it in my calculator im getting 32! yea?

ohh so like .5 hours?

okay great! so one third of 96 is 32. what is two-thirds of 96?

would i add 32 + 32? = 64?

very good! so 2/3 of 96 minutes is 64 minutes. how many minutes in an hour?

60 so its one hour 4 minutes?

exactly! you can write your answer as 1 hour 4 minutes or (64/60) hours which is the same as 1.067 hours

and I have another question I just need to figure out what method to use: Find the sum of the solutions of the equation: 2x\[^{2}\] +5x-3

use factorisation

2 * -3 = -6 think of combinations you can use to get 5x from factors of -6

like -6 and 1?

wait thats negative 5

yup but -6 +1 = -5x, not 5x think of another combination

okay are we adding the two factors? So like 2 +3= 5

yes, 2+3 =5, but 2 times 3 is 6 we want -6 so 2 and 3 is not the correct combination

okay, 6 plus -1 !! :)

very good!

go ahead and factorize it now

omg that took a long time! haha okay i got (2x+6) and (x-1)

no you should get (2x-1) and (x+3)

then do i set them both to equal zero and solve or am i done with the solution

the question asks to find the sum of the solution..

\[2x ^{2}+5x-3 =0 \] \[2x ^{2}+6x-x-3 =0 \] \[2x (x+3)-1(x+3) =0\] \[(2x-1)(x-3)=0\] \[x = \frac{1}{2}, -3\]

phenomenal, thank you thank you! and another thing when two slopes are parallel does that mean there slopes are the same?

yes. it also means that there is no point of intersection.

slopes cannot be parallel, only lines can be parallel. I assume you meant lines, not slopes in your question.

oh okay okay yes I meant lines. for example 2/3 and 2/3 would be parallel lines correct?

and if the question gives you a 4 quadrant grid and there is a triangle drawn on it and they ask how long is side AB , could you use the distance formula : "d= the square root of x2-x1) squared plus (y2-y1) squared ???

yes

Okay thank you! You have truly been a help to me even so late! I am studying for my placement exam to College algebra at a community college and i think i got it i appreciate it!

you are very knowledgeable, you should consider tutoring!

lol, i wouldn't be any good at it. and you are welcome :)

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