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OpenStudy (anonymous):
\[\int\limits_{?}^{?} e ^{u}\]
OpenStudy (anonymous):
The integral of e^u is e^u + c
OpenStudy (anonymous):
I got that from my calculus book
OpenStudy (anonymous):
is it e^u*u'?
OpenStudy (anonymous):
which one is tht?
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OpenStudy (anonymous):
the integral is e^u
OpenStudy (anonymous):
so e^(1-x) is what?
OpenStudy (anonymous):
\[\int\limits_{?}^{?}e^u = e^u + C\]
OpenStudy (anonymous):
\[\int\limits e^u du= e^u\]
OpenStudy (anonymous):
yes +C integration constant
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OpenStudy (anonymous):
what is the integral of \[5^{-x}\]
OpenStudy (anonymous):
-5^-x/ln5 +C
OpenStudy (anonymous):
watz the deriv of e^u>?
OpenStudy (anonymous):
Example: If you want to solve \[\int\limits_{?}^{?}e ^{3x+1}dx\] then you rewrite it by doing a substitution with u\[\int\limits_{}^{?}e^udu\], when u=3x+1, then du=3, therefore you write this as:\[(1/3)\int\limits_{?}^{?}e^udu\]=\[(1/3)e^u = (1/3)e ^{3x+1} + C\]
OpenStudy (anonymous):
sorry, du=3dx
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OpenStudy (anonymous):
ohhok got it thankssss:)
OpenStudy (anonymous):
integral rule for ln u?
OpenStudy (anonymous):
You will need to integrate by parts to solve that one.