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OpenStudy (anonymous):

find formula for the sum of n terms.then find limit as n->infiniti for...

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OpenStudy (anonymous):

\[\lim_{n \rightarrow \infty} \sum_{i=1}^{n} (2i/n)(2/n)\]

OpenStudy (anonymous):

2nd 2 last que for the day!:)

OpenStudy (anonymous):

this one's similar to the other question you had simplify the sigma to something that's easier to apply the sumation formulas. so 1st simplify it to ∑4i/n^2. you want to get ∑i in the end, so take out the 4/n^2 and put that in front of the ∑ to get (4/n^2)∑i. the formula for ∑i was (n^2+n)/2 so from there on, you can do simple algebra to get the answer :)

OpenStudy (anonymous):

ohhh..got it! thank u soo much again!:)

OpenStudy (anonymous):

you're welcome!

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